Dec. 1st, 2012

redfiona99: (Thinking)
Based on something that happened to me in RL.

We have 3 cards, marked E, S and F. They are drawn 8 times. What is the probability of the draw being:

1 - E, S, F
2 - E, S, F
3 - S, E, F
4 - E, S, F
5 - S, F, E
6 - E, S, F
7 - S, E, F
8 - S, F, E

Now they were all supposed to be independently drawn, so I think I have to add the probability of each independent draw rather than multiplying them. What's confusing me is whether or not each line is 1/3 x 1/2 or whether I have to take into account the probability of the first pick when I work out the probability of the second pick.

(In case anyone is wondering what the RL scenario was, it was the running order for weapons in a match, randomised so no-one would have an advantage. I just want to know why Lady Luck kept putting me (Foil) on last.)

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